50=2x^2+16x+32

Solution for 50=2x^2+16x+32 equation:

50=2x^2+16x+32

We move all terms to the left:

50-(2x^2+16x+32)=0

We get rid of parentheses

-2x^2-16x-32+50=0

We add all the numbers together, and all the variables

-2x^2-16x+18=0

a = -2; b = -16; c = +18;
Δ = b2-4ac
Δ = -162-4·(-2)·18
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*-2}=\frac{-4}{-4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*-2}=\frac{36}{-4}
=-9
$